Ideal Gas Equation
1.2 Exercise 3 - Ideal Gas Equation
Remember: R = 8.31 JK-1mol-1, 0 K = -273 oC
1. Calculate the
volume occupied by one mole of a gas at 25 oC and 100 kPa.
2. Calculate the
pressure of a gas given that 0.2 moles of the gas occupy 10 dm3 at
20 oC.
3. Calculate the
temperature of a gas if 0.5 moles occupy 1.2 dm3 at a pressure of 200
kPa.
4. Calculate the
mass of a sample of carbon dioxide which occupies 20 dm3 at 27 oC
and 100 kPa.
5. Calculate the
relative molecular mass of a gas if a 500 cm3 sample at 20 oC
and 1 atm has a mass of 0.66 g.
6. At 25 oC
and 100 kPa a gas occupies a volume of 20 dm3. Calculate the new
temperature of the gas if
a) the volume is
decreased to 10 dm3 at constant pressure.
b) the pressure is
decreased to 50 kPa at constant volume.
7. 10.0 g of calcium nitrate is heated at 100 kPa
and a temperature of 300 oC, at which temperature it fully
decomposes. Calculate
a) the
volume of nitrogen dioxide evolved
b) the
volume of oxygen evolved
c) the
total volume of gas evolved
Equation:
2Ca(NO3)2(s) à 2CaO(s) + 4NO2(g) + O2(g)
8. Calculate the volume of oxygen produced at 298 K and 100 kPa
by the decomposition of 30 cm3 of 0.1 moldm-3 hydrogen
peroxide.
Equation: 2H2O2(aq) à 2H2O(l) + O2(g)
9. Lead (IV) oxide dissolves in
concentrated hydrochloric acid according to the following equation: PbO2(s) + 4HCl(aq) à PbCl2(s) + Cl2(g) + 2H2O(l)
Starting with 37.2 g of lead (IV) oxide, calculate:
a) the volume of 12 moldm-3 HCl needed to completely dissolve it
b) the mass of PbCl2 produced
c) the volume of chlorine produced at 298 K and 100 kPa.
10. What mass of magnesium, and what volume of 2.0 moldm-3 hydrochloric acid, will be
required to produce 100 cm3 of hydrogen gas
at 298 K and 100 kPa?
Equation: Mg(s) + 2HCl(aq) à MgCl2(aq) + H2(g)
11. 0.52 g of sodium was added to 100 cm3 of water. Calculate:
a) The
volume of hydrogen evolved at 298 K and 100 kPa
b) The concentration of the sodium
hydroxide solution produced, assuming the volume of water does not change.
Equation: 2Na(s) + 2H2O(l) à 2NaOH(aq) + H2(g)
This comment has been removed by a blog administrator.
ReplyDelete